5x^2+3x-64+48-20=0

Solution for 5x^2+3x-64+48-20=0 equation:

5x^2+3x-64+48-20=0

We add all the numbers together, and all the variables

5x^2+3x-36=0

a = 5; b = 3; c = -36;
Δ = b2-4ac
Δ = 32-4·5·(-36)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-27}{2*5}=\frac{-30}{10}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+27}{2*5}=\frac{24}{10}
=2+2/5
$